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authorQuinn Harris <btcdev@quinnharris.me>2013-11-05 19:07:16 -0300
committerbitcoindev <bitcoindev@gnusha.org>2013-11-05 22:26:54 +0000
commitc6914101dcb7d5188b90190467231032ab0419d1 (patch)
treecd67baf8a6662e4a8c12847e756c0011e7360702
parentea97078c488f1b9890ee592ad27c7a2c1e0cf696 (diff)
downloadpi-bitcoindev-c6914101dcb7d5188b90190467231032ab0419d1.tar.gz
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Re: [Bitcoin-development] Possible Solution To SM Attack
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+Message-ID: <52796C14.5070300@quinnharris.me>
+Date: Tue, 05 Nov 2013 19:07:16 -0300
+From: Quinn Harris <btcdev@quinnharris.me>
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+Subject: Re: [Bitcoin-development] Possible Solution To SM Attack
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+
+I don't think choosing the block with the lowest hash is the best
+option. The good and bad miners have an equal probability of finding a
+lower hash. But after Alice finds a block she can easily determine the
+probability that someone else will find a lower hash value that meets
+the difficulty requirement. This can be used to judge if its best to
+start working on the next block or work on finding a lower value hash to
+increase the chance her block is used.
+
+Its better if the block is chosen in a way that doesn't let Alice know
+the probability her block will be chosen. One simple possibility is to
+start at the least significant bit of the hash and whichever has a 1 is
+chosen and if both bits are the same the next bit is used.
+
+This should be pseudo random and not give Alice any knowledge ahead of
+time if her block will be chosen. This would prevent the network hash
+power from being split between two branches unlike each node choosing a
+random block.
+
+Quinn
+
+On 11/05/2013 05:51 PM, colj@Safe-mail.net wrote:
+> Preliminary:
+> Alice has the ability to hear of a block before all other miners do.
+>
+> The Problem:
+> Say Alice built a block, A1, from previous block 0. She doesn't let other miners know about it. She then works on A2 with previous block A1. Bob on the other hand is still working on B1 with previous block 0. Bob now finds a block and he broadcasts it. The assumption here is Alice will be the first miner to hear of this block and she will send her previously mined block, A1, to all other miners. By the time Bobs block arrives to other miners majority of them will already have received Block A1 and Bobs block will most likely be orphaned. Alice revealed her block, A1, only when Bob broadcast his block. This means she has been mining on block A2 with previous block A1 for longer than any other miner thus gaining an advantage without increasing her hash rate.
+>
+> What We Know:
+> Alice has gained an advantage with time. She mines longer on the valid block.
+> In order for this attack to work Alice must reveal her previously mined block as late as possible, gaining her the most time spent working on the valid block. Since she has such good view of the Bitcoin network she can wait until a miner finds a block to release her previously mined block.
+>
+> The most obvious sign of this attack taking place is the timing. A miner will receive a block and very quickly hear of another block both built from the same previous block.
+>
+> The block that a miner hears first is the one which will be mined on.
+>
+> Possible Solution:
+> If N amount of blocks built of the same previous block are received within a time frame of T mine on the block with the lowest hash.
+>
+> Logic:
+> In order for Alice to pull of this attack she not only has to propagate her blocks first she must also ensure her blocks are of the smallest hash.
+>
+> Alice would now have to decrease her target to pull of this attack. Since she has a lower target it will take her longer to find a valid block negating her time advantage.
+>
+>
+> colj
+>
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+