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#!/usr/bin/env python
"""
linelen.py - print max line length of each input file, assuming no tabs.
Also print line number of at least one line which is that long.
@author: Bruce
@version: $Id$
@copyright: 2007-2009 Nanorex, Inc. See LICENSE file for details.
"""
import sys, os, time
# bruce 070304, added lineno 090126
def linelen(fn):
"""
Given filename fn,
return max line length (assuming no tabs and all lines \n-terminated),
and one of the line numbers it occurs on (the first one, in current implem).
"""
file = open(fn, 'rU')
lines = file.readlines()
file.close()
if not lines:
return 0, 0
rawlengths = map(len, lines)
maxlen = max(rawlengths) - 1 # -1 is for the terminating newline
###BUG if file ends non-\n
###BUG if file contains tabs
lineno = 1 + rawlengths.index(maxlen + 1)
return maxlen, lineno
# ==
if __name__ == '__main__':
filenames = sys.argv[1:]
program = os.path.basename(sys.argv[0])
if not filenames:
msg = "usage: %s <files> [no stdin reading supported for now]" % (program,)
print >> sys.stderr, msg
sys.exit(1)
for fn in filenames:
if os.path.isfile(fn):
maxlen, lineno = linelen(fn)
print "linelen(%r) = %d (line %d)" % (fn, maxlen, lineno)
else:
print "not found or not a plain file: %r" % fn
continue
print "done"
# end
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